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DICOM PS3.17 2020a - Explanatory Information |
(PXt, PYt, PZt)T= (R3 · R2 · R1) · ((PX, PY, PZ)T- (TX, TY, TZ)T)
(PXt, PYt, PZt)A = (136.99, -95.41, -32.48) in mm.
Step 7: Image B: Point (PXt, PYt, PZt)B in Table coordinates
In this step, the table has moved from image A to image B. The table coordinates of the object of interest are the same on image A and image B because it is assumed that the patient is fixed on the table.
(PXt, PYt, PZt)B = (136.99, -95.41, -32.48) in mm.
Step 8: Image B: Point (PX, PY, PZ)B in Isocenter coordinates
In this step, the isocenter coordinates (PX, PY, PZ)B are calculated from the table coordinates (PXt, PYt, PZt)B by taking into account the table position and angles of the image B in the Isocenter coordinate system:
Tx =Table X Position to Isocenter = 20.0 mm
Ty =Table Y Position to Isocenter = 100.0 mm
Tz =Table Z Position to Isocenter = 0.0 mm
At1 = Table Horizontal Rotation Angle = 0.0 deg
At2 = Table Head Tilt Angle = 10.0 deg
At3 = Table Cradle Tilt Angle = 0.0 deg
(PX, PY, PZ)T= (R3 · R2 · R1)T· (PXt, PYt, PZt)T+ (TX, TY, TZ)T
(PX, PY, PZ)B = (156.99, -12.11, -48.55) in mm.
Step 9: Image B: Point (PXp, PYp, PZp)B in positioner coordinates
Inthisstep,thepositionercoordinates(PXp,PYp,PZp)B arecalculatedfromtheisocentercoordinates(PX,PY,PZ)B bytakingintoaccount the positioner angles of the image B in the Isocenter coordinate system:
Ap1 = Positioner Isocenter Primary Angle = -30.0 deg
Ap2 = Positioner Isocenter Secondary Angle = 0.0 deg
Ap3 = Positioner Isocenter Detector Rotation Angle = 0.0 deg
(PXp, PYp, PZp)T= R3 · ((R2 · R1) · (PX, PY, PZ)T)
(PXp, PYp, PZp)B = (142.01, 68.00, -48.55) in mm.
Step 10: Image B: Point ( Pu, Pv)B in positioner coordinates
In this step, the (Pu, Pv)B coordinates in mm are calculated from the positioner coordinates (PXp, PYp, PZp)B by taking into account the Distance Source to Detector and the Distance Source to Isocenter of the image B: